What is the value of h(0) in the function h(x) = -10x² + 280x + 17,400?

To find the value of h(0) in the function h(x) = -10x² + 280x + 17,400, you need to substitute x with 0 in the equation and then simplify it.

Start by substituting 0 into the function:

h(0) = -10(0)² + 280(0) + 17,400.

Now, evaluate each term:

• The first term, -10(0)², evaluates to -10 times 0, which is 0.

• The second term, 280(0), also evaluates to 0.

• The constant term is simply 17,400.

Adding these values together gives:

h(0) = 0 + 0 + 17,400 = 17,400.

Hence, the value of h(0) is indeed 17,400. This calculation directly demonstrates that the correct answer reflects the constant term in the quadratic function when x is zero, without any other contributions from the variable terms.