What is the value of x in the equation (53)(3+x) = (252)(x+3)?

To solve the equation ( (53)(3 + x) = (252)(x + 3) ), we can start by distributing both sides.

On the left side, we have:

[

53 \times 3 + 53 \times x = 159 + 53x

]

On the right side, we have:

[

252 \times x + 252 \times 3 = 252x + 756

]

Now, the equation becomes:

[

159 + 53x = 252x + 756

]

Next, we can rearrange this equation by moving all the terms involving ( x ) to one side and the constant terms to the other side. To do this, we can subtract ( 53x ) from both sides:

[

159 = 252x - 53x + 756

]

This simplifies to:

[

159 = 199x + 756

]

Now, isolate ( 199x ) by subtracting ( 756 ) from both sides:

[

159 - 756 = 199x

]

[

-597 = 199x

]

To find ( x ), we