A family of twelve spent $266 on circus tickets, with adult tickets costing $23 and children's tickets $21. How many adults attended?

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Multiple Choice

A family of twelve spent $266 on circus tickets, with adult tickets costing $23 and children's tickets $21. How many adults attended?

Explanation:
To determine the correct number of adults who attended the circus, we can set up a system of equations based on the information provided. Let \( a \) represent the number of adults and \( c \) represent the number of children. We know from the problem that: 1. The total number of family members (adults and children) is 12. \[ a + c = 12 \] 2. The total amount spent on tickets is $266, with adult tickets costing $23 each and children's tickets costing $21 each. \[ 23a + 21c = 266 \] We can solve this system step by step. First, we can express \( c \) in terms of \( a \) from the first equation: \[ c = 12 - a \] Next, we substitute this expression for \( c \) into the second equation: \[ 23a + 21(12 - a) = 266 \] Expanding this gives: \[ 23a + 252 - 21a = 266 \] Combining like terms results in: \[ 2a + 252 = 266 \] Now

To determine the correct number of adults who attended the circus, we can set up a system of equations based on the information provided. Let ( a ) represent the number of adults and ( c ) represent the number of children.

We know from the problem that:

  1. The total number of family members (adults and children) is 12.

[

a + c = 12

]

  1. The total amount spent on tickets is $266, with adult tickets costing $23 each and children's tickets costing $21 each.

[

23a + 21c = 266

]

We can solve this system step by step. First, we can express ( c ) in terms of ( a ) from the first equation:

[

c = 12 - a

]

Next, we substitute this expression for ( c ) into the second equation:

[

23a + 21(12 - a) = 266

]

Expanding this gives:

[

23a + 252 - 21a = 266

]

Combining like terms results in:

[

2a + 252 = 266

]

Now

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